C++ (constructor selection, shadowing, and references) — determine the output after calling SetValue and Display.\n\n#include<iostream.h>\nclass CuriousTab {\n int x; float y;\npublic:\n CuriousTab(int x) { x = x; }\n CuriousTab(int p = 0, int q = 10) { x = p += 2; y = q * 1.0f; }\n void SetValue(int &y, float z) { x = y; y = (int)z; }\n void Display(void) { cout << x; }\n};\nint main() {\n int val = 12;\n CuriousTab objCuriousTab(val);\n CuriousTab objTmp();\n objCuriousTab.SetValue(val, 3.14f);\n objCuriousTab.Display();\n return 0;\n}\n\nWhat is printed?

Introduction / Context:
This question explores constructor overload choice when defaults are present, name shadowing inside constructors, the most-vexing parse, and effects of passing by reference. It asks what value is ultimately printed by Display().

Given Data / Assumptions:

• Two constructors: CuriousTab(int) and CuriousTab(int,int) (the latter has defaults).
• Call CuriousTab objCuriousTab(val); with val = 12.
• CuriousTab objTmp(); is a function declaration (most-vexing parse), not an object.
• SetValue(int& y, float z) assigns to the member and mutates the caller’s variable.

Concept / Approach:
Overload resolution prefers the exact single-argument match (CuriousTab(int)) over using a default parameter in the two-argument constructor. Inside that constructor, the parameter name shadows the member, so x = x; assigns the parameter to itself and leaves the member x uninitialized (though it will be assigned later). SetValue(val, 3.14f) sets the member x to 12 and then casts 3.14f to 3 and stores it back into val via the reference.

Step-by-Step Solution:

Verification / Alternative check:
Had the two-arg ctor been chosen, x would become p += 2. But default-argument overload is not preferred over the exact one-parameter constructor here.

Why Other Options Are Wrong:

• 2: Misreads the second constructor as selected.
• Errors: The program compiles and runs (with legacy headers).

Common Pitfalls:
Name shadowing in constructors (x = x;) and misinterpreting CuriousTab objTmp(); as an object instead of a function declaration.

Final Answer:
The program will print the output 12.