Difficulty: Medium
Correct Answer: 8 μs
Explanation:
Introduction / Context:Counter (ramp) type ADCs perform conversion by counting clock pulses until the DAC output matches or exceeds the analog input. The worst-case time occurs when the input is near full scale and the counter must traverse almost all codes.
Given Data / Assumptions:
Concept / Approach:Worst-case conversion time T_wc ≈ (2^n) / f_clk for an n-bit counter-type ADC. Some treatments use (2^n − 1), but with comparator/DAC settling, the nominal worst-case closely tracks 2^n counts.
Step-by-Step Solution:
n = 4 ⇒ 2^n = 16 counts.Clock period = 1 / 2 MHz = 0.5 μs.T_wc ≈ 16 * 0.5 μs = 8 μs.Verification / Alternative check:Using (2^n − 1) * T_clk = 15 * 0.5 μs = 7.5 μs; with practical settling and control overhead, 8 μs is the accepted figure among given options.
Why Other Options Are Wrong:
10 μs: would imply fewer counts per μs than available.2 μs or 5 μs: underestimate required counts.Common Pitfalls:
Confusing average conversion time (~ half worst case) with worst case.Final Answer:
8 μs
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