Refining chemistry – converting normal paraffins Which refinery process converts n-paraffins to i-paraffins, thereby improving octane number?
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AAlkylation
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BPolymerisation
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CIsomerisation
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Dnone of these
Answer
Correct Answer: Isomerisation
Explanation
Introduction / Context:Octane improvement can be achieved by altering hydrocarbon structure. Straight-chain paraffins have low octane; branching increases octane. Refineries use specific catalytic routes to rearrange molecules without major carbon number change.
Given Data / Assumptions:
- Feed contains normal paraffins (e.g., C4–C6).
- Goal: increase branching to raise octane while preserving carbon number.
- Low-temperature catalytic processes under hydrogen are available.
Concept / Approach:Isomerisation catalytically rearranges straight-chain paraffins into isoparaffins. Over bifunctional catalysts (e.g., Pt on chlorided alumina or zeolites), skeletal rearrangement proceeds with minimal cracking, significantly boosting octane in light naphtha pools.
Step-by-Step Solution:
Identify structural change: straight-chain → branched.Choose process that rearranges but does not add/remove carbon atoms → isomerisation.Thus, isomerisation is correct.Verification / Alternative check:Process flow diagrams for light naphtha isomerization units confirm production of isopentane/isomerized C6, improving pool octane.
Why Other Options Are Wrong:
- Alkylation: Combines isobutane with light olefins to form higher isoparaffins; not a simple n-paraffin → i-paraffin rearrangement.
- Polymerisation: Joins small olefins into larger molecules; different objective.
- None of these: Incorrect because isomerisation is the standard route.
Common Pitfalls:Confusing isomerisation (rearrangement) with cracking (carbon number change). Operating severity must avoid excessive cracking to retain yield.
Final Answer:Isomerisation