Refining chemistry – converting normal paraffins Which refinery process converts n-paraffins to i-paraffins, thereby improving octane number?

Difficulty: Easy

Correct Answer: Isomerisation

Explanation:


Introduction / Context:
Octane improvement can be achieved by altering hydrocarbon structure. Straight-chain paraffins have low octane; branching increases octane. Refineries use specific catalytic routes to rearrange molecules without major carbon number change.


Given Data / Assumptions:

  • Feed contains normal paraffins (e.g., C4–C6).
  • Goal: increase branching to raise octane while preserving carbon number.
  • Low-temperature catalytic processes under hydrogen are available.


Concept / Approach:
Isomerisation catalytically rearranges straight-chain paraffins into isoparaffins. Over bifunctional catalysts (e.g., Pt on chlorided alumina or zeolites), skeletal rearrangement proceeds with minimal cracking, significantly boosting octane in light naphtha pools.


Step-by-Step Solution:

Identify structural change: straight-chain → branched.Choose process that rearranges but does not add/remove carbon atoms → isomerisation.Thus, isomerisation is correct.


Verification / Alternative check:
Process flow diagrams for light naphtha isomerization units confirm production of isopentane/isomerized C6, improving pool octane.


Why Other Options Are Wrong:

  • Alkylation: Combines isobutane with light olefins to form higher isoparaffins; not a simple n-paraffin → i-paraffin rearrangement.
  • Polymerisation: Joins small olefins into larger molecules; different objective.
  • None of these: Incorrect because isomerisation is the standard route.


Common Pitfalls:
Confusing isomerisation (rearrangement) with cracking (carbon number change). Operating severity must avoid excessive cracking to retain yield.


Final Answer:
Isomerisation

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