8-bit binary form of a small decimal Convert the decimal number 35 to an 8-bit binary value (show leading zeros).

Introduction / Context:
Expressing small decimal integers in a fixed 8-bit binary format is routine when initializing registers, masks, and configuration values. Leading zeros are preserved to keep the full 8-bit width, which is important for clarity and alignment in low-level work.

Given Data / Assumptions:

• Decimal input: 35.
• Target width: 8 bits.
• Standard base-2 place values are used.

Concept / Approach:
Decompose 35 into powers of two. 35 = 32 + 2 + 1 = 2^5 + 2^1 + 2^0. Set bits at those positions and clear the rest. Finally, pad with leading zeros to form 8 bits.

Step-by-Step Solution:

Verification / Alternative check:
Convert back: 00100011₂ = 32 + 2 + 1 = 35 decimal, confirming correctness.

Why Other Options Are Wrong:

• 00100000: equals 32.
• 00100010: equals 34.
• 00100100: equals 36.

Common Pitfalls:
Dropping leading zeros or misplacing the 2^1 and 2^0 bits when forming the lower three bits.

Final Answer:
00100011