A right circular cone (solid metal) of height 8 cm and base radius 2 cm is melted and recast into a sphere. Find the radius of the sphere.

Difficulty: Easy

Correct Answer: 2 cm

Explanation:


Introduction / Context:
This is a volume-conservation recasting problem: a cone is melted and remade into a sphere. Since material is conserved, cone volume equals sphere volume; we solve for the new radius.


Given Data / Assumptions:

  • Cone height h = 8 cm.
  • Cone radius r = 2 cm.
  • No loss of material; V_cone = V_sphere.


Concept / Approach:

  • V_cone = (1/3)*π*r^2*h.
  • V_sphere = (4/3)*π*R^3.
  • Equate and solve for R.


Step-by-Step Solution:

V_cone = (1/3)*π*(2)^2*(8) = (1/3)*π*32 = (32/3)π cm^3Set (32/3)π = (4/3)π*R^3 ⇒ cancel (π, 1/3): 32 = 4*R^3R^3 = 8 ⇒ R = 2 cm


Verification / Alternative check:
Back-substitute: V_sphere = (4/3)π*8 = (32/3)π, exactly the cone volume; consistent.


Why Other Options Are Wrong:

  • 3, 4, 5 cm: Give sphere volumes that are too large.
  • None of these: Not applicable; 2 cm is exact.


Common Pitfalls:

  • Using diameter in place of radius in volume formulas.
  • Arithmetic errors when equating and simplifying.


Final Answer:
2 cm

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