C#.NET Generics — interpret the where-constraint. Given: public class MyContainer<T> where T : IComparable { // Insert code here } Which statements are valid? Class MyContainer requires that its type argument must implement the IComparable interface. The type argument of class MyContainer must be IComparable itself (not just implement it). The compiler will report an error for this block of code. This requirement placed on the type argument is called a constraint.

Introduction / Context:
This question checks your understanding of generic type constraints in C#. The keyword where specifies requirements that any type argument T must satisfy for a generic class or method.

Given Data / Assumptions:

• Generic class: MyContainer<T>.
• Constraint: where T : IComparable.
• We assume the interface name is correctly spelled IComparable and is accessible.

Concept / Approach:
A where T : IComparable constraint means “T must implement IComparable (or be IComparable itself).” This is called a generic constraint. If the interface name is valid and in scope, there is no compile-time error solely due to the constraint.

Step-by-Step Solution:

Verification / Alternative check:
Instantiate with MyContainer<string> (valid, since string implements IComparable) and MyContainer<int> (valid, since int implements IComparable).

Why Other Options Are Wrong:
Options that include (2) are incorrect because they claim the type must equal the interface type, not simply implement it. Options that include (3) wrongly state the code will not compile.

Common Pitfalls:
Confusing “implements interface” with “must be the interface type itself.” Also, forgetting to add using System; if referencing IComparable.

Final Answer:
1 and 4 Only