Data Sufficiency — Coding (“one”) How is the word “one” coded? I. “one of its kind” → zo pi ko fe; “in kind and cash” → ga to ru ko. II. “its point for origin” → ba le fe mi; “make a point a clear” → yu si mi de. III. “make money and cash” → to mi ru hy; “money of various kind” → qu ko zo hy.

Difficulty: Hard

Correct Answer: Statements I and III together are sufficient; otherwise not.

Explanation:


Introduction / Context:
We must map words↔codes by intersecting phrases.


Given Data / Assumptions:

  • I pairs {one, of, its, kind} with {zo, pi, ko, fe}; and “in kind and cash” with {ga, to, ru, ko} ⇒ “kind” ↔ ko by intersection; thus {zo, pi, fe} map to {one, of, its} in some order.
  • II involves none of {one, of} explicitly (except “its” appears giving fe), but does not isolate “one”.
  • III gives overlap “cash” (ru/to) and “money”, “of”, “kind” with new codes; “of” intersects I and III to disambiguate.


Concept / Approach:
Use intersections to fix unique mappings. From I we know ko=kind and fe=its (since “its” appears in I and II: “its” maps to fe). Then in I the remaining {zo, pi} are {one, of}. Using III (“money of various kind” → qu ko zo hy) with ko=kind fixes “of”→zo, hence “one”→pi.


Step-by-Step Solution:

1) From I and II: fe=its; ko=kind.2) In I: {zo, pi} ↔ {one, of}.3) From III with “of” present and ko fixed, the remaining shared code becomes zo=of.4) Therefore, “one” = pi.


Why Other Options Are Wrong:
I alone leaves two candidates for “one”; II alone irrelevant; III alone insufficient. I+III together suffice; all three not required.


Final Answer:
“one” is coded as pi; sufficiency: I and III together.

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