Difficulty: Easy
Correct Answer: 29
Explanation:
Introduction:
The average molecular weight of dry air is required in numerous calculations, including gas densities, flow metering, and psychrometrics.
Given Data / Assumptions:
Concept / Approach:
The apparent molecular weight is a mole-fraction-weighted average of component molar masses. Using standard atmospheric proportions yields a value close to 28.96 g/mol, commonly rounded to 29 g/mol for engineering work.
Step-by-Step Solution:
Approximate calculation: M_air ≈ 0.7828 + 0.2132 + 0.01*40 ≈ 21.84 + 6.72 + 0.40 ≈ 28.96 g/mol.Round to the standard engineering value: 29 g/mol.Use 29 g/mol in density and molar flow computations unless high precision with real composition is needed.
Verification / Alternative check:
Textbook tables and property databases list dry air ≈ 28.96 g/mol (often rounded to 29 g/mol).
Why Other Options Are Wrong:
Common Pitfalls:
Using 28 g/mol (nitrogen) instead of the mixture average; neglecting argon and CO₂ contributions when high accuracy is required.
Final Answer:
29
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