Liquid–liquid extraction – distribution coefficient (partition ratio) In a ternary system of two immiscible liquids and a solute at equilibrium, the ratio of solute concentrations in the two phases is called the distribution coefficient. On what does this coefficient primarily depend?

Difficulty: Easy

Correct Answer: both(a) & (b)

Explanation:


Introduction / Context:
The Nernst distribution law governs how a solute partitions between two immiscible solvents. This partition ratio, or distribution coefficient, is fundamental for designing extraction stages and predicting required solvent rates.


Given Data / Assumptions:

  • Dilute solutions and ideal behavior assumed initially.
  • Two immiscible liquid phases in contact at equilibrium.
  • Temperature can alter solubility and activity coefficients.


Concept / Approach:
For truly dilute, non-associating systems, the distribution coefficient can be nearly constant, but in real systems it is affected by solute concentration (non-ideal activity effects, dimerization/association) and temperature (changes in solubility parameters and activity coefficients). Therefore, both temperature and concentration influence K_D to varying degrees, and extraction data are typically reported as a function of both variables.


Step-by-Step Solution:

Define K_D = C_solute,phase1 / C_solute,phase2 at equilibrium.Recognize activity-coefficient dependence: γ(T, x) changes with composition and temperature.Conclude that both concentration and temperature affect K_D.Select the combined option acknowledging both influences.


Verification / Alternative check:
Tie-line data in ternary diagrams show K_D varying with composition and shifting with temperature, corroborating the dependence.


Why Other Options Are Wrong:

  • Only concentration or only temperature: Incomplete; both exert measurable effects.
  • Neither: Contradicts empirical extraction data and thermodynamic models.


Common Pitfalls:
Assuming K_D constant over wide ranges; this can mispredict stage counts. Always consult phase-equilibrium data at the operating temperature and composition.


Final Answer:
both(a) & (b)

More Questions from Stoichiometry

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion