Difficulty: Easy
Correct Answer: The Calvin cycle (dark reactions / light-independent reactions)
Explanation:
Introduction / Context:
Photosynthesis has two broad phases: light reactions that capture solar energy to form ATP and NADPH, and the Calvin cycle that uses those energy carriers to reduce carbon dioxide into organic molecules. This question asks where the actual chemical reduction of CO2 occurs.
Given Data / Assumptions:
Concept / Approach:
The Calvin cycle comprises carboxylation, reduction, and regeneration phases. CO2 is first fixed to ribulose 1,5-bisphosphate, then reduced at the 1,3-bisphosphoglycerate → glyceraldehyde-3-phosphate step, using NADPH and ATP supplied by the light reactions. Thus, reduction of CO2 is a hallmark of the Calvin cycle, not of the photochemical charge-separation events themselves.
Step-by-Step Solution:
Verification / Alternative check:
Isotopic labeling (14CO2) and stoichiometric measurements show that electron equivalents from NADPH are consumed during the reduction phase in the stroma, confirming the Calvin cycle as the site of CO2 reduction.
Why Other Options Are Wrong:
Common Pitfalls:
Equating energy generation (light reactions) with carbon reduction; the former supplies energy, the latter uses it in the Calvin cycle.
Final Answer:
The Calvin cycle (dark reactions / light-independent reactions)
Discussion & Comments