Difficulty: Easy
Correct Answer: An electric field
Explanation:
Introduction / Context:
Capacitors are fundamental components in electrical and electronics engineering. They store energy when a potential difference is applied across their two plates separated by an insulating medium (the dielectric). Understanding the physical form of this stored energy clarifies how capacitors behave in filters, timing circuits, and energy buffering applications.
Given Data / Assumptions:
Concept / Approach:
Energy in a capacitor is stored in the electric field established in the dielectric. The field intensity E is related to the voltage V and plate separation d. The energy stored is given by the scalar formulas commonly used in circuit analysis: U = 0.5 * C * V^2 or equivalently in field terms U = 0.5 * ∫(E * D) dV (qualitative understanding only here). There is no magnetic field energy unless time-varying currents create one externally; the capacitor itself stores energy electrostatically.
Step-by-Step Solution:
Recognize that applied voltage causes charge separation across the dielectric.An electric field E forms within the dielectric proportional to voltage and geometry.Energy density in the dielectric depends on E and dielectric properties.Therefore the energy is stored as an electric field, not a magnetic field or a sign-labeled voltage.
Verification / Alternative check:
Removing the voltage source but leaving the capacitor isolated retains charge and voltage, consistent with energy stored in the established electric field between plates.
Why Other Options Are Wrong:
A magnetic field: associated mainly with inductors and current flow, not static capacitor energy.Positive/negative voltage: voltage is a potential difference, not a physical form of stored energy.
Common Pitfalls:
Confusing electric field storage (capacitors) with magnetic field storage (inductors).Assuming energy is stored as “voltage” rather than in the field within the dielectric.
Final Answer:
An electric field
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