Difficulty: Easy
Correct Answer: None of these
Explanation:
Introduction / Context:
Days-of-week questions reduce to modular arithmetic modulo 7. Each span of 7 days returns the calendar to the same weekday. We only need the remainder of the day count when divided by 7 to shift forward from the given day.
Given Data / Assumptions:
Concept / Approach:
Compute 363 mod 7 to get the net weekday shift. 7 × 51 = 357; 363 − 357 = 6. Therefore, we move 6 days ahead from Thursday.
Step-by-Step Solution:
Remainder = 363 mod 7 = 6.Starting Thursday, +6 days: Friday (1), Saturday (2), Sunday (3), Monday (4), Tuesday (5), Wednesday (6).Therefore, the target day is Wednesday.
Verification / Alternative check:
Because 364 is divisible by 7, 363 is one day short of a full-week multiple; being one short of a multiple of 7 means “previous day” relative to Thursday + 7k, i.e., Wednesday.
Why Other Options Are Wrong:
Sunday, Saturday, and Thursday do not correspond to a +6 shift from Thursday; they represent remainders 3, 2, and 0 respectively.
Common Pitfalls:
Accidentally counting inclusively (starting at 0) or going backward instead of forward by the remainder.
Final Answer:
None of these (the correct day is Wednesday)
Discussion & Comments