Calendar arithmetic — If 2 June 2012 was a Saturday, what day of the week was 7 July 2012?

Introduction / Context:
Within the same year, we can find the weekday on a later date by counting the exact number of days between them and taking it modulo 7.

Given Data / Assumptions:

• 2 June 2012 was Saturday.
• Target date: 7 July 2012.
• Number of days between dates determines the weekday shift.

Concept / Approach:
Compute days difference from 2 June to 7 July and reduce mod 7.

Step-by-Step Solution:
Days remaining in June after the 2nd = 28 days (from June 3 to June 30).Plus first 7 days of July = 7 days.Total difference = 28 + 7 = 35 days.35 mod 7 = 0 → No weekday change.So the day remains Saturday.

Verification / Alternative check:
35 days equals exactly 5 weeks; hence same weekday.

Why Other Options Are Wrong:
They imply a non-zero shift in weekday, which contradicts the 35-day (multiple of 7) interval.

Common Pitfalls:
Off-by-one counting (including the start date incorrectly) or forgetting that complete weeks preserve the weekday.

Final Answer:
Saturday.