C programming — determine whether these two structs can be compared with ==.\n\n#include<stdio.h>\n\nint main()\n{\n struct emp\n {\n char n[20];\n int age;\n };\n struct emp e1 = {"Dravid", 23};\n struct emp e2 = e1;\n\n if (e1 == e2)\n printf("The structures are equal");\n return 0;\n}\n\nWhat is the correct assessment?

Introduction / Context:
The question targets whether C permits comparing entire structures using the == operator. Copying one struct to another is allowed, but comparison is a different rule.

Given Data / Assumptions:

• Two struct emp variables e1 and e2 exist and contain identical field values.
• An if condition attempts e1 == e2.

Concept / Approach:
Standard C allows assignment between compatible structure types (e2 = e1) but does not define == or != for entire structure operands. You must compare field-by-field, e.g., using strcmp for character arrays and direct comparison for integers.

Step-by-Step Solution:

Verification / Alternative check:
Compilers emit an error like “invalid operands to binary == (have struct emp and struct emp)”. Fieldwise comparison compiles and behaves as expected.

Why Other Options Are Wrong:

• Prints equal: Impossible; code does not compile.
• No output unspecified: The problem occurs at compile time, not runtime.
• Runtime crash due to padding: Padding is unrelated; the operator itself is illegal.

Common Pitfalls:
Assuming struct comparison works like in C++ or in some compiler extensions. In portable C, compare members explicitly.

Final Answer:
Error: Structure cannot be compared using '=='