What will be the output of the program? #include int main() { union a { int i; char ch[2]; }; union a u; u.ch[0]=3; u.ch[1]=2; printf("%d, %d, %d ", u.ch[0], u.ch[1], u.i); return 0; }

What will be the output of the program? #include<stdio.h> int main() { union a { int i; char ch[2]; }; union a u; u.ch[0]=3; u.ch[1]=2; printf("%d, %d, %d ", u.ch[0], u.ch[1], u.i); return 0; }

3, 2, 515
515, 2, 3
3, 2, 5
515, 515, 4

Correct Answer: 3, 2, 515

Explanation:

The system will allocate 2 bytes for the union.

The statements u.ch[0]=3; u.ch[1]=2; store data in memory as given below.

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