What will be the output of the program? #include char *str = "char *str = %c%s%c; main(){ printf(str, 34, str, 34);}"; int main() { printf(str, 34, str, 34); return 0; }

Question

What will be the output of the program? #include<stdio.h> char *str = "char *str = %c%s%c; main(){ printf(str, 34, str, 34);}";  int main() {     printf(str, 34, str, 34);     return 0; }

Accepted Answer

char *str = "char *str = %c%s%c; main(){ printf(str, 34, str, 34);}"; main(){ printf(str, 34, str, 34);}

What will be the output of the program? #include<stdio.h> char str = "char str = %c%s%c; main(){ printf(str, 34, str, 34);}"; int main() { printf(str, 34, str, 34); return 0; }

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