What will be the output of the program? #include char *str = "char *str = %c%s%c; main(){ printf(str, 34, str, 34);}"; int main() { printf(str, 34, str, 34); return 0; }

Question

What will be the output of the program? #include<stdio.h>
char *str = "char *str = %c%s%c; main(){ printf(str, 34, str, 34);}";

int main()
{
    printf(str, 34, str, 34);
    return 0;
}

Accepted Answer

char *str = "char *str = %c%s%c; main(){ printf(str, 34, str, 34);}"; main(){ printf(str, 34, str, 34);}

What will be the output of the program? #include char str = "char str = %c%s%c; main(){ printf(str, 34, str, 34);}"; int main() { printf(str, 34, str, 34); return 0; }