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What will be the output of the program? #include int main() { char ch; if(ch = printf("")) printf("It matters\n"); else printf("It doesn't matters\n"); return 0; }

Correct Answer: It doesn't matters

Explanation:

printf() returns the number of charecters printed on the console.


Step 1: if(ch = printf("")) here printf() does not print anything, so it returns '0'(zero).
Step 2: if(ch = 0) here variable ch has the value '0'(zero).
Step 3: if(0) Hence the if condition is not satisfied. So it prints the else statements.
Hence the output is "It doesn't matters".


Note: Compiler shows a warning "possibly incorrect assinment".


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