Point out the error, if any in the program. #include<stdio.h>
int main()
{
int i = 1;
switch(i)
{
printf("This is c program.");
case 1:
printf("Case1");
break;
case 2:
printf("Case2");
break;
}
return 0;
}
Correct Answer: No Error and prints "Case1"
Explanation:
switch(i) becomes switch(1), then the case 1: block is get executed. Hence it prints "Case1".
printf("This is c program."); is ignored by the compiler.
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