Home » C Programming » Control Instructions

Point out the error, if any in the program. #include int main() { int i = 1; switch(i) { printf("This is c program."); case 1: printf("Case1"); break; case 2: printf("Case2"); break; } return 0; }

Correct Answer: No Error and prints "Case1"

Explanation:

switch(i) becomes switch(1), then the case 1: block is get executed. Hence it prints "Case1".


printf("This is c program."); is ignored by the compiler.


Hence there is no error and prints "Case1".


← Previous Question Next Question→

More Questions from Control Instructions

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion