Macro that prints integers without spaces: what will this program output exactly? #include #define PRINT(i) printf("%d,", i) int main() { int x = 2, y = 3, z = 4; PRINT(x); PRINT(y); PRINT(z); return 0; }

Macro that prints integers without spaces: what will this program output exactly? #include<stdio.h> #define PRINT(i) printf("%d,", i) int main() { int x = 2, y = 3, z = 4; PRINT(x); PRINT(y); PRINT(z); return 0; }

Difficulty: Easy

2,3,4,
2, 3, 4,
2, 2, 2,
3, 3, 3,
Compilation error from macro

Correct Answer: 2,3,4,

Explanation:

Introduction / Context:
The task emphasizes exact output formatting. The macro prints an integer followed by a comma with no trailing space. When invoked three times, the outputs concatenate exactly as they are emitted, producing a compact string with commas but no spaces.

Given Data / Assumptions:

#define PRINT(i) printf("%d,", i)
Variables: x=2, y=3, z=4.
No other characters or spaces are printed.

Concept / Approach:
Each call writes the decimal value and a comma. Since the format string does not include a space (e.g., "%d, "), the characters appear back-to-back: 2, then comma, then 3, comma, then 4, comma. There is no newline unless added explicitly elsewhere.

Step-by-Step Solution:

First call: prints 2,.Second call: prints 3, immediately after.Third call: prints 4, immediately after.Final console line: 2,3,4,.

Verification / Alternative check:
Change the macro to "%d, " and re-run; you will then see spaces: 2, 3, 4,.

Why Other Options Are Wrong:

Options with spaces do not match the exact format string.Repeated identical numbers would require passing the same variable each time.Compilation errors do not occur here.

Common Pitfalls:
Ignoring whitespace in format strings; assuming the console inserts spaces automatically (it does not).

Macro that prints integers without spaces: what will this program output exactly? #include<stdio.h> #define PRINT(i) printf("%d,", i) int main() { int x = 2, y = 3, z = 4; PRINT(x); PRINT(y); PRINT(z); return 0; }

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