Macro-defined infinite loop – will this program print the message endlessly?\n\n#include <stdio.h>\n#define INFINITELOOP while(1)\n\nint main()\n{\n INFINITELOOP\n printf("CuriousTab");\n return 0;\n}

Introduction / Context:
This program uses a macro to represent an infinite loop and asks whether the subsequent printf is executed repeatedly. Understanding macro expansion and loop syntax is required.

Given Data / Assumptions:

• #define INFINITELOOP while(1)
• In main, the macro appears directly before printf.

Concept / Approach:
After preprocessing, the code becomes while(1)printf("CuriousTab"); which is a standard while loop whose body is the single statement printf("CuriousTab");. Since the condition is always true, the body executes forever, repeatedly printing the message.

Step-by-Step Solution:
Expand macro: INFINITELOOP → while(1).Interpretation: loop body is the next statement, i.e., printf.Because the condition is true, the loop never terminates; printing occurs continuously.

Verification / Alternative check:
Add braces to limit scope: INFINITELOOP { break; } or rewrite as for(;;) to observe similar infinite behavior. Inserting a break or changing the condition to while(0) alters the outcome.

Why Other Options Are Wrong:
Prints once — contradicted by the loop. No output — false because the loop body calls printf. Does not compile — the construct is valid; a semicolon is not required after while(1) when a statement follows.

Common Pitfalls:
Forgetting braces in loops leading to only the next statement being controlled; assuming macros need semicolons; not flushing output or buffering effects (output may be buffered, but it still loops).

Final Answer:
Yes, it will print endlessly