In C, does the . operator access members from a structure variable (as opposed to a pointer)?

Introduction / Context:Member access syntax is fundamental in C. The . operator and the -> operator apply to different operand types.

Given Data / Assumptions:

• A structure (or union) value.
• A pointer to such a value may also exist.

Concept / Approach:Use . when you have an actual object; use -> when you have a pointer. This rule is identical for structs and unions.

Step-by-Step Solution:1) Let s be a struct value: access as s.member.2) Let ps be a pointer: access as ps->member (i.e., (*ps).member).3) Therefore . is correct for variables, while -> is for pointers.

Verification / Alternative check:Compilers enforce this; using . on a pointer produces an error unless you dereference first.

Why Other Options Are Wrong:Option B: Reverses the rule.
Option C: C has no public/private for structs.
Option D: Nesting does not change the operator rule.
Option E: . and -> are not interchangeable.

Common Pitfalls:Forgetting to dereference pointers or assuming both operators behave the same leads to confusing errors.

Final Answer:Correct — use . with a structure (or union) variable, not a pointer.