C comma operator in an expression: determine the output. #include<stdio.h> int main() { int i=2; int j = i + (1, 2, 3, 4, 5); printf("%d ", j); return 0; }

Introduction / Context:The comma operator in C evaluates each operand from left to right and yields the value of the last operand. Inside parentheses, a sequence like (1, 2, 3, 4, 5) therefore evaluates to 5. This question tests recognition of the comma operator's semantics when used inside a larger arithmetic expression.

Given Data / Assumptions:

• i = 2.
• Expression: j = i + (1, 2, 3, 4, 5).
• No side effects beyond evaluation order.

Concept / Approach:The comma operator is often confused with the comma separating function arguments. In expressions, it is a legitimate operator with low precedence whose result is the last subexpression. Parentheses ensure the comma sequence is treated as a single operand to the plus operator.

Step-by-Step Solution:

Verification / Alternative check:Replace the last value with another number (e.g., ... , 9) to see the output change correspondingly; the earlier values are discarded except for side effects if present.

Why Other Options Are Wrong:

Common Pitfalls:Confusing the comma operator with argument separators; overlooking its low precedence and the need for parentheses to bind it tightly.

Final Answer:7.