Dishonest dealer with multiple cheats — Cost price is ₹ x per kg. He buys at 20% discount and by false weighing receives 20% extra quantity from the wholesaler. He marks up by 80% on x, gives a 25% discount to customers, and also short-weighs them by 10%. What is his overall profit percentage?

Introduction / Context:
This composite problem features both buying-side and selling-side manipulations. On the buy side, he pays a discounted price and also receives extra quantity; on the sell side, he uses a high markup, gives a discount, and short-weighs customers. Converting everything to “per true kg” values reveals the net effect.

Given Data / Assumptions:

• List cost = x per kg; he pays 20% less ⇒ pays 0.80x per nominal kg.
• By false weigh-in from the wholesaler, 1 paid kg yields 1.20 true kg.
• Marked price = 1.80x per kg; customer discount = 25% ⇒ SP per nominal kg = 1.35x.
• Short-weigh to customers: delivers 0.90 true kg per nominal kg billed.

Concept / Approach:
Compute effective CP per true kg and SP per true kg, then use Profit% = (SP_true − CP_true)/CP_true * 100.

Step-by-Step Solution:

Verification / Alternative check:
Choose x = 100: CP_true = ₹ 66.67; SP_true = ₹ 150 ⇒ profit ₹ 83.33 ⇒ 125% of 66.67.

Why Other Options Are Wrong:
100%, 98.66%, and 120% misapply one or more factors; 80% omits part of the compounded effect.

Common Pitfalls:
Mixing nominal and true kilograms, or applying the 25% discount on cost instead of on the marked price.

Final Answer:
125%