Brake power measurement with a rope brake: Assume a rope brake dynamometer around a drum. Using effective radius Re = (D + d) / 2, the brake power (B.P.) is ________ (use W = dead load, S = spring balance reading, N = rpm).

Difficulty: Medium

Correct Answer: B.P. = (2 * pi * N / 60) * (W - S) * Re

Explanation:


Introduction / Context:
Brake power (B.P.) is the usable power delivered at the engine shaft. A rope brake dynamometer is a simple device to measure torque via a dead weight and a spring balance around a brake drum. Getting the sign and effective radius right is key to accurate power calculation.



Given Data / Assumptions:

  • Rope brake around a drum of diameter D with rope diameter d.
  • Dead load W (N) hangs on one side; spring balance reads S (N) on the other.
  • Effective radius Re = (D + d) / 2 (in metres).
  • Shaft speed N (rpm).


Concept / Approach:
Torque T equals net circumferential force times effective radius. The net force causing braking is (W − S). Power equals torque times angular speed. Angular speed in rad/s is 2 * pi * N / 60. Combine to obtain B.P.



Step-by-Step Solution:

Compute net force: F = W − S.Effective radius: Re = (D + d) / 2.Torque: T = F * Re.Angular speed: omega = 2 * pi * N / 60.Brake power: B.P. = T * omega = (2 * pi * N / 60) * (W − S) * Re.


Verification / Alternative check:
Dimensional check: N is rpm, so 2 * pi * N / 60 gives s^-1; multiplying by torque (N·m) yields watts, confirming consistency.



Why Other Options Are Wrong:

  • Using (W + S) overestimates torque; the opposing forces act in opposite directions so net is W − S.
  • Dividing by Re instead of multiplying inverts torque dimensionally.
  • Both incorrect sign and inverse radius compound the error.


Common Pitfalls:
Forgetting rope thickness in effective radius or misreading the spring balance direction. Also, ensure steady state (no acceleration) so that net torque equals measured braking torque.



Final Answer:
B.P. = (2 * pi * N / 60) * (W - S) * Re

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