Boolean product evaluation: Confirm the fundamental identity 1 · 0 = 0 in Boolean algebra, where “·” denotes logical AND.

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
Boolean algebra underpins digital logic. The AND operation corresponds to multiplication-like behavior where the result is true only if all operands are true. Verifying basic identities like 1 · 0 = 0 ensures accurate reasoning about gates and circuits.


Given Data / Assumptions:

  • Binary values use 1 for HIGH/true and 0 for LOW/false.
  • AND truth: true only when both inputs are true.
  • We are working at the logical, not analog, level.


Concept / Approach:
By the AND definition, if any input is 0, the output must be 0. Therefore, 1 AND 0 is 0, and 0 AND 1 is 0, and 0 AND 0 is 0. Only 1 AND 1 yields 1. These form the core truth table reflected in gate behavior and in Boolean equations.


Step-by-Step Solution:

Define AND: output = 1 only when all inputs = 1.Evaluate 1 · 0: at least one input is 0 → output = 0.Conclude identity: 1 · 0 = 0 holds universally in Boolean algebra.Relate to gate: an AND gate fed by inputs 1 and 0 drives 0.


Verification / Alternative check:
Truth table check: rows (1,0) and (0,1) both give 0. Algebraic properties (annihilator for AND) also state that 0 is the absorbing element: X · 0 = 0 for any X.


Why Other Options Are Wrong:
“Incorrect” contradicts the AND definition. “Only true in arithmetic” misunderstands the mapping between Boolean AND and multiplication-like behavior. “Depends on voltage thresholds” addresses implementation details, not the abstract Boolean law.


Common Pitfalls:
Mixing arithmetic and logic but forgetting the identical outcome for this specific case; considering analog exceptions that are beyond Boolean abstraction.


Final Answer:
Correct

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