TCA Cycle—Identify the First Isolated Intermediate What is the first stable intermediate formed when acetyl-CoA enters the tricarboxylic acid (TCA) cycle?

Difficulty: Easy

Correct Answer: Citrate

Explanation:


Introduction / Context:
The TCA cycle begins when acetyl-CoA condenses with oxaloacetate. Knowing the sequence of intermediates is essential for tracing carbon flow and understanding regulation points in central metabolism.


Given Data / Assumptions:

  • Entry substrate: acetyl-CoA (2 carbons).
  • Acceptor: oxaloacetate (4 carbons).
  • Enzyme: citrate synthase.


Concept / Approach:
Citrate synthase catalyzes condensation of acetyl-CoA with oxaloacetate to form citrate (6 carbons) via an intermediate citryl-CoA. Citrate is the first stable and isolable TCA intermediate after entry, preceding isomerization to isocitrate by aconitase.


Step-by-Step Solution:

Combine acetyl-CoA (2C) + oxaloacetate (4C) → citrate (6C).Recognize citrate as the first product after the entry condensation step.Note subsequent steps: citrate → isocitrate via aconitase (not required for this answer).


Verification / Alternative check:
Enzyme assays for citrate synthase activity and accumulation of citrate in conditions of aconitase inhibition corroborate this sequence.


Why Other Options Are Wrong:

  • Succinate, fumarate, malate: later TCA intermediates.
  • Oxaloacetate: the acceptor that reacts with acetyl-CoA; not the first product formed after entry.


Common Pitfalls:
Confusing oxaloacetate (the acceptor) with citrate (the first product).


Final Answer:
Citrate

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