Difficulty: Easy
Correct Answer: Four nitrogens of heme and the proximal histidine (five-coordinate)
Explanation:
Introduction:
Hemoglobin’s function depends on how the Fe(II) center is coordinated in the heme pocket. In deoxyhemoglobin, Fe(II) is high-spin and five-coordinate; in oxyhemoglobin, binding O2 gives a sixth ligand and low-spin character.
Given Data / Assumptions:
Concept / Approach:
Count coordination number and identify axial ligands. In deoxy Hb, there is no bound O2 or water at the sixth site; the distal His does not coordinate directly but stabilizes ligands via H-bonding when present.
Step-by-Step Solution:
Verification / Alternative check:
Spectral and structural data show a five-coordinate, high-spin Fe(II) in deoxy Hb and six-coordinate, low-spin Fe(II) in oxy Hb.
Why Other Options Are Wrong:
Options with water or multiple histidines misrepresent deoxy coordination. A water ligand occurs in some met or aquo states, not in deoxy Hb.
Common Pitfalls:
Confusing distal His (non-bonding in deoxy) with a coordinating ligand; assuming O2/water present in the deoxygenated state.
Final Answer:
Four nitrogens of heme and the proximal histidine (five-coordinate)
Discussion & Comments