Difficulty: Easy
Correct Answer: None of these
Explanation:
Introduction / Context:
Beta decay comes in two forms: β− (electron emission) and β+ (positron emission). Textbooks emphasize that lepton number and energy must be conserved, which introduced the neutrino concept historically. Many students mistakenly think γ rays always accompany β emission.
Given Data / Assumptions:
Concept / Approach:
In β− decay, a neutron converts to a proton with the emission of an electron and an antineutrino. In β+ decay, a proton converts to a neutron with the emission of a positron and a neutrino. Thus, a (anti)neutrino is the unavoidable partner in β processes; γ emission is optional and occurs only if the daughter nucleus remains excited.
Step-by-Step Solution:
β−: n → p + e− + anti-ν (antineutrino).β+: p → n + e+ + ν (neutrino).“Always” clause: neutrino/antineutrino is required; γ is not guaranteed.Given options do not include neutrino explicitly as the correct choice among A–D, hence “None of these.”
Verification / Alternative check:
Energy spectra of β particles are continuous because energy is shared with the (anti)neutrino, confirming its obligatory presence; discrete γ lines are not a universal feature of β decay.
Why Other Options Are Wrong:
Gamma rays: common but not guaranteed; many β decays go straight to ground state.Alpha particles and neutrons: define different decay modes altogether.Option E explains the truth but is not among A–D; the keyed answer among A–D is therefore “None of these.”
Common Pitfalls:
Memorizing “β always with γ” without the neutrino caveat.Confusing “often” with “always” in exam phrasing.
Final Answer:
None of these
Discussion & Comments