Palindromic triplets with uniform +2 steps across positions.
- First letters: B → D → F → H → J (+2).
- Middle letters: C → E → G → I → K (+2).
- Last letters mirror the first: B → D → F → H → J.
Concept/ApproachIdentify symmetry (1st = 3rd) and apply a consistent +2 stride.Step-by-Step calculationCompute next letters: (H+2, I+2, H+2) = (J, K, J) ⇒ JKJ.Verification/AlternativeAlphabet indices: B(2),D(4),F(6),H(8),J(10); C(3),E(5),G(7),I(9),K(11).Common pitfallsBreaking the palindrome or using a +1 step at any position.Final AnswerJKJ
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