Difficulty: Easy
Correct Answer: 6.023 × 10^23 molecules per gram-mole
Explanation:
Introduction / Context:Avogadro’s number links the microscopic count of particles to macroscopic amounts in moles. It is fundamental to stoichiometry, gas laws, and conversion between mass and number of particles for any chemical species.
Given Data / Assumptions:
Concept / Approach:The definition associates the gram-mole (simply “mole” in SI) with 6.02×10^23 entities. Options using kilogram-mole would scale the count differently and are not the standard definition for “per gram-mole.” Thus, the correct choice is 6.023 × 10^23 molecules per gram-mole (mol).
Step-by-Step Solution:
Recall: 1 mol contains NA ≈ 6.02 × 10^23 entities.Identify units: “per gram-mole” means per mole.Select option with 10^23 per gram-mole.Reject options with kilogram-mole or incorrect powers of ten.Verification / Alternative check:Consult any physical constants table; the count per mole is ~6.02 × 10^23, independent of substance.
Why Other Options Are Wrong:
Common Pitfalls:Confusing kmol and mol; industrial gas calculations often use kmol but the particle count scales accordingly.
Final Answer:6.023 × 10^23 molecules per gram-mole
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