Difficulty: Medium
Correct Answer: 910
Explanation:
Introduction / Context:
This is a classic selection and ratio problem involving total candidates, selected candidates and unselected candidates. It checks the ability to translate ratio statements into algebraic equations and then solve for the total number of participants. This type of question appears frequently in competitive exams to test reasoning with ratios, totals and hypothetical changes.
Given Data / Assumptions:
Concept / Approach:
First, we express the original numbers of selected and unselected candidates in terms of a common variable using the ratio 6 : 1. That also gives us the original total number of candidates. Next, we adjust these numbers according to the hypothetical situation: subtract 30 from the total and 10 from the selected, and deduce the new unselected count from the new total. Using the new ratio 7 : 1, we get an equation in the variable. Solving this equation yields the original total number of applicants.
Step-by-Step Solution:
Verification / Alternative check:
Originally, selected = 6 * 130 = 780, unselected = 130. Ratio = 780 : 130 = 6 : 1 (correct). In new scenario: total = 910 - 30 = 880, selected = 780 - 10 = 770, unselected = 880 - 770 = 110. New ratio = 770 : 110 = 7 : 1, which matches the condition. So the answer 910 is confirmed.
Why Other Options Are Wrong:
Common Pitfalls:
Some learners may incorrectly subtract 30 only from selected or only from unselected instead of from the total. Others may forget to recalculate the new unselected count from the new total and new selected. Keeping track of each adjusted number and carefully forming the ratio equation is essential to avoid mistakes.
Final Answer:
The original number of candidates who applied for the process is 910.
Discussion & Comments