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The sum of length, breadth and height of a cuboid is 22 cm and the length of its diagonal is 14 cm. What is the surface area of the cuboid?

Correct Answer: 288 sq.cm

Explanation:

Let lengths, breadth and height of cuboid be l, b and h respectively

According to question

l+b+h = 22cm......(i)

and

√(l^2+b^2+h^2) = 14cm .....(ii)

Surface area of cuboid = 2(lb+bh+lh)

Squaring eq (i) gives

l 2 + b 2 + h 2 + 2(lb+bh+lh) = 484

Substituting l^2+b^2+h^2 from eq (i)

2(lb+bh+lh) = 484 -196 = 288 sq.cm

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