A spherical ball of lead, 3 cm in diameter is melted and recast into three spherical balls, The diameter of two of these are 1.5 cm and 2 cm respectively. The diameter of the third ball is?

Q: A spherical ball of lead, 3 cm in diameter is melted and recast into three spherical balls, The diameter of two of these are 1.5 cm and 2 cm respectively. The diameter of the third ball is?

∵ 4/3πr 3 = 4/3π x [(3/2) 3 - {(3/4) 3 + 1 3 } ] ⇒ r 3 = 125/64 = (5/4) 3 ⇒ r = 5/4 ∴ Diameter = (5/4) x 2 cm = 2.5 cm.

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Accepted Answer

∵ 4/3πr³ = 4/3π x [(3/2)³ - {(3/4)³ + 1³ } ]
⇒ r³ = 125/64 = (5/4)³
⇒ r = 5/4
∴ Diameter = (5/4) x 2 cm = 2.5 cm.

A spherical ball of lead, 3 cm in diameter is melted and recast into three spherical balls, The diameter of two of these are 1.5 cm and 2 cm respectively. The diameter of the third ball is?

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