A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

Correct Answer: 3 m

Explanation:

Area of the park = (60 x 40) = 2400 sq.m

Area of the lawn = 2109 sq.m

Area of the crossroads = (2400 - 2109) = 291 sq.m

Let the width of the road be x metres. Then,

60x + 40x - (x * x) = 291

=>(x * x) - 100x + 291 = 0

=>(x - 97)(x - 3) = 0

=>x=3

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