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The radius of a wire is decreased to one-third. If volume remains the same, length will increase?

Correct Answer: 9 times

Explanation:

Let original radius = r and original length = h
New radius = r/3
Let new length = H
Then, π r2h = π (r/3)2 x H = π r2H/9
∴ H = 9h
Thus, the length becomes 9 times .


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