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If the radius of a sphere is increased by 3%, then what percent increase takes place in surface area of the sphere?

6.09%
7%
5.06%
9%

Correct Answer: 6.09%

Explanation:

According to the formula
Percentage increase in surface area = [ 2x + x²/100]%
= [2 x 3 + (3)²/100]%
= [6 + 0.09]%
= 6.09%

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