If each edge of a cube is increased by 50%, find the percentage increase in Its surface area

Correct Answer: 125%

Explanation:

Let the edge = a cm

So increase by 50 % = a + a/2 = 3a/2

Total surface Area of original cube = $6 a 2$

TSA of new cube = $6 \frac{3 a}{2} 2$ = $6 \frac{9 a 2}{4}$ = $13.5 a 2$

Increase in area = $13.5 a 2 - 6 a 2$ = $7.5 a 2$

$7.5 a 2$ Increase % = $\frac{7.5 a 2}{6 a 2} \times 100$ = 125%

More Questions from Volume and Surface Area

No comments yet. Be the first to comment!