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A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3, then the weight of the pipe is:

Correct Answer: 3.696 kg

Explanation:

External radius = 4 cm,

Internal radius = 3 cm.



Volume of iron
= 22 x [(4)2 - (3)2] x 21 ❩cm3
7
= 22 x 7 x 1 x 21 ❩cm3
7
= 462 cm3.


∴ Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.


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