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A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:

49 m2
50 m2
53.5 m2
55 m2

Correct Answer: 49 m2

Explanation:

Area of the wet surface	= [2(lb + bh + lh) - lb]
	= 2(bh + lh) + lb
	= [2 (4 x 1.25 + 6 x 1.25) + 6 x 4] m²
	= 49 m².

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