A can do a piece of work in 24 days. If B is 60% more efficient than A, then the number of days required by B to do the same piece of work is?

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Accepted Answer

Efficiency of A = 4.16% Efficiency of B = 1.6 x 4.16 = 6.66% ∴ Number of days required by B = 100/6.66 = 15 days

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