A can do a certain job in 10 days. B is 60% more efficient than A. The number of days, it takes B to do the same piece of work is?

6
61/4
62/3
8

Correct Answer: 62/3

Explanation:

1 day work of A = 1/10 = 0.1
1 day work of B = 1/10 + 60% of 1/10 = 0.1 + 0.06 = 0.16
So number of days taken by B to complete the work = 1/0.16
= 6²/₃

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