A and B together finish a wor in 20 days.They worked together for 15 days and then B left. Afer another 10 days,A finished the remaining work. In how many days A alone can finish the job?

Q: A and B together finish a wor in 20 days.They worked together for 15 days and then B left. Afer another 10 days,A finished the remaining work. In how many days A alone can finish the job?

(A+B)'s 15 days work = 1 20 × 15 = 3 4 Remaining work = 1/4 Now, 1/4 work is done by A in 10 days. Whole work will be done by A in (10 x 4) = 40 days.

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40
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Correct Answer: 40

Explanation:

(A+B)'s 15 days work = $\frac{1}{20} \times 15 = \frac{3}{4}$

Remaining work = 1/4

Now, 1/4 work is done by A in 10 days.

Whole work will be done by A in (10 x 4) = 40 days.

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