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A alone can do a work in 20 days. B is 125% more efficient than A. A and B started working and worked for 4 days. If C alone completed the remaining job in 22 days. How many days C alone takes to complete the entire job?

Correct Answer: 40

Explanation:

A alone can do = 20days

Efficiency ratio of A & B= 4 : 5

Time required will be in ratio = 5:4

B alone will do it in =16 days

LCM of (16,20)= 80 ,

Assume work size of 80 units

1 day work of A= 4 units 1 day work of B= 5 units

Work done by both in 4 days= 4*(5+4)= 36 units

Work left= 80-36= 44 units

Now C takes 22 days to complete= 44 units.

Time taken by C alone to complete the work= 40 days

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