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A is 3 times faster than B. If A can finish a work 32 days less than that of B, find the number of days need to finish the work if both are working together?

Correct Answer: 12 days

Explanation:

It is given that efficiency ratio =3:1


so time ratio will be 1:3 (since work is same)


 


Also given that time diff = 32 days. ratio difference = 3-1 =2 


2 ratio = 32 days


1 ratio = 16 days.


So A will alone finish it in 16 days and B will finish it in 16*3 = 48 days.


 


Total work = LCM of 16 and 48 = 48.


Total time = Total work/Total efficiency 


ie; 48/4= 12 days.


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