A train running at 8/11 of its own speed reached a place in 5 1/ 2 h. How much time could be saved, if the train would have run as its own speed?

21/2 h
2 h
11/2 h
1 h

Correct Answer: 11/2 h

Explanation:

New speed = 8/11 of usual speed
New time = 11/8 of usual time
∴ 11/8 of usual time = 11/2 h
⇒ Usual time = (11 x 8)/(2 x 11) = 4 h
∴ Time saved = 5¹/₂- 4
= 1¹/₂

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