Home » Aptitude » Time and Distance

A thief is spotted by a policeman from a distance of 200 m. When the policeman starts chasing, the thief also starts running. If the speed of the thief be 16 km/h and that of the policeman be 20 km/h, how far the thief will have run before he is overtaken?

Correct Answer: 800 m

Explanation:

Relative speed of policeman = ( 20 - 16 ) x 5/18 = 10/9 m/s
To catch the thief, the policeman in has to gain 200 m = 200 x 9/10 = 180 s
Actual distance covered by policeman in 180 s = 180 x 50/9 = 100 m
∴ Distance covered by the thief = 1000 - 200 = 800m


← Previous Question Next Question→

More Questions from Time and Distance

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion