Shard cover two-third of a certain distance at 4 km/hr and the remaining at 5 km/hr. If he takes 42 minutes in all, the distance is?

Question

Accepted Answer

Let total distance be y km. Then , (2y / 3) / 4 + ( y / 3) / 5 = 42/60 ⇒ y/6 + y/ 15 = 7/10 ⇒ 5y + 2y = 21 ∴ y = 3 ∴ Required distance = 3 km.

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