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A man is riding a bike with front and back wheel circumference of 40 inches and 70 inches respectively. If the man rides the bike on a straight road without slippage, how many inches will the man have travelled when the front wheel has made 15 revolutions more than the back wheel?

Correct Answer: 1400

Explanation:

Given the ratio of the circumference of front wheel  is 40 inches and back wheel is 70 inches. 


 


Distance covered = Circumference of the wheel × No. of Revolutions made by the wheel


 


If n is the number of revolutions made by back wheel, the number of revolutions made by front wheel is n+15


 


Distance covered by both the wheels is the same


 


i.e, 40*(n+15)=70n


 


 n=20 


 


 


 


                Front wheel      :      Back Wheel 


 


 Circumference       40      :      70 


 


 Revolutions           35      :      20


 


 


 


Distance covered  :  40×35 = 70×20 = 1400 inches.


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