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A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:

Correct Answer: 40

Explanation:

Let distance = x km and usual rate = y kmph.



Then, x - x = 40   ⟹   2y(y + 3) = 9x ....(i)
y y + 3 60



And, x - x = 40   ⟹   y(y - 2) = 3x ....(ii)
y -2 y 60


On dividing (i) by (ii), we get: x = 40.


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