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The distance of the college and home of Rajeev is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed (or increased) speed of Rajeev?

Correct Answer: 20 km/h

Explanation:

Let the normal speed be x km/h, then 


80 x - 80 ( x + 4 ) = 1


x 2 + 4 x - 320 = 0


x (x + 20) - 16 (x + 20) = 0


(x + 20 ) (x - 16) =0


 


x = 16 km/h


 Therefore (x + 4) = 20 km/h


 Therefore increased speed = 20 km/h


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